F(x)=2x^2-36x+88

Solution for F(x)=2x^2-36x+88 equation:

(F)=2F^2-36F+88

We move all terms to the left:

(F)-(2F^2-36F+88)=0

We get rid of parentheses

-2F^2+F+36F-88=0

We add all the numbers together, and all the variables

-2F^2+37F-88=0

a = -2; b = 37; c = -88;
Δ = b2-4ac
Δ = 372-4·(-2)·(-88)
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{665}}{2*-2}=\frac{-37-\sqrt{665}}{-4}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{665}}{2*-2}=\frac{-37+\sqrt{665}}{-4}
$